You are watching: Do the diagonals of a rhombus bisect the angles
With that being said, ns was wonder if within parallel the diagonals bisect the angle which the meet.
For instance, please describe the link, go $\\overlineAC$ bisect $\\angle BAD$ and also $\\angle DCB$?
If they diagonals do certainly bisect the angles which castle meet, might you please, in layman\"s terms, show your proof?
edited may 21 \"20 at 10:41
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request Jun 3 \"16 in ~ 16:45
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$\\begingroup$ Yes yet not a typical parallelogram, only in a square, rhombus and also kite. $\\endgroup$
Jun 3 \"16 in ~ 17:11
2 answers 2
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The diagonals bisect angles only if the sides are all of equal length.
Assume that the diagonals certainly bisect angles.
Then $\\angle BCE=\\angle ECD$ in your diagram.
Also $\\angle ECD=\\angle EAB$ because $AB \\| DC$.
So $\\angle BCE = \\angle EAB$, thus $\\triangle BAC$ is isosceles through $AB=BC$.
Similar arguments likewise prove equality of various other sides, $BC=CD$ and also $CD=DA$.
answer Jun 3 \"16 at 16:53
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Nope it doesn\"t...We deserve to prove it using congruency triangle.U deserve to see that vertically the opposite angles are equal.Not the diagonal line bisect angle
answered may 15 \"19 at 5:11
HEPIN RAJESHBHAI SAVALIYAHEPIN RAJESHBHAI SAVALIYA
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