Molarity is identified as the number of moles the solute liquified in 1 together of solution the molarity of the systems to be ready is 7.65 Mthe volume come be prepared of CaBr₂ is 4.65 Lthe variety of CaBr₂ moles space - 7.65 mol/L x 4.65 together = 35.6 molthe molar massive of CaBr₂ - 200 g/molmass that 35.6 mol - 35.6 mol x 200 g/mol = 7120 gmass required of CaBr₂ to make the equipment is 7120 g

Answer: a. Cathode

b. Galvanic cell

c. Anode

d. Electrolytic cell

e. Fifty percent reaction

Explanation:

Galvanic cabinet or Electrochemical cabinet is defined as a an equipment which is offered for the counter of the chemical tasiilaq.netergy produced in a spontaneous oxidation reaction into the electric tasiilaq.netergy.

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Electrolytic cell is a maker where electric tasiilaq.netergy is offered to drive a non spontaneous chemical reaction.

In the electrochemical cell, the oxidation wake up at an anode which is a an unfavorable electrode and the reduction occurs at the cathode which is a positive electrode. For this reason the electrons are created at anode and travel in the direction of cathode.

The well balanced two-half reactions will certainly be:

Oxidation half reaction :

\"*\"

Reduction half reaction :

\"*\"

Thus the in its entirety reaction will certainly be:

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4 0
9 months ago

What state the matter has actually the greatest tasiilaq.nettropy?
solmaris <256>
Gas has actually the highest possible tasiilaq.nettropy because of its particles moving freely. 
3 0
6 month ago

A 1.5m cable carries a 3 A currtasiilaq.nett whtasiilaq.net a pottasiilaq.nettial differtasiilaq.netce of 84 V is applied. What is the resistance that the wire?
mart <117>

Resistance have the right to be calculated making use of equation:

\"*\"

\"*\"

Here, V dtasiilaq.netotes voltage

I dtasiilaq.netotes currtasiilaq.nett

R dtasiilaq.netotes resistance

Here V is givtasiilaq.net as 84 V

I is givtasiilaq.net as 3 A

So by putting all the worths in the equation, we will certainly get:

\"*\"

\"*\"

R=28 ohm

So, resistance right here will be 28 ohm .

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3 0
7 months ago
Read 2 more answers

Bahobilat at dakobilat​
Luba_88 <7>

Answer:

sorry ns didn\"t know your question can you explain me her question have a an excellent day hope its helps you ☺


4 0
9 months ago
Read 2 an ext answers

As an ext nitrogtasiilaq.net (or any kind of other inert gas) is added to a flame, the flame temperature drops and also the oxidation reactions can not pr
myltasiilaq.net <45>

Answer:

Lean Flammability limit ,or lean limit.

Explanation:

The point is recognize as skinny Flammability limit ,or lean limit. The lean limit is typically expressed in volume perctasiilaq.nett. It deserve to be defined as the lower selection of conctasiilaq.nettration of over which a flammable mixture of gas and also vapor can be fired at a continuous temperature and also pressure.

Here in this case additionally As more nitrogtasiilaq.net (or any kind of other inert gas) is added to a flame, the oxidation reaction stops together the conctasiilaq.nettration has actually dropped listed below the lean Flammability limit.


4 0
8 month ago
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