LCM that 15 and also 25 is the the smallest number among all common multiples of 15 and also 25. The first couple of multiples that 15 and 25 space (15, 30, 45, 60, 75, . . . ) and (25, 50, 75, 100, 125, 150, 175, . . . ) respectively. There space 3 generally used approaches to discover LCM that 15 and also 25 - through listing multiples, by division method, and by element factorization.

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1.LCM the 15 and 25
2.List of Methods
3.Solved Examples
4.FAQs

Answer: LCM of 15 and 25 is 75.

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Explanation:

The LCM of 2 non-zero integers, x(15) and also y(25), is the smallest confident integer m(75) the is divisible through both x(15) and also y(25) without any type of remainder.


The methods to discover the LCM of 15 and 25 are explained below.

By element Factorization MethodBy Listing MultiplesBy department Method

LCM of 15 and also 25 by prime Factorization

Prime administer of 15 and 25 is (3 × 5) = 31 × 51 and (5 × 5) = 52 respectively. LCM the 15 and 25 have the right to be obtained by multiplying prime factors raised to their respective highest possible power, i.e. 31 × 52 = 75.Hence, the LCM that 15 and 25 by element factorization is 75.

LCM of 15 and 25 by Listing Multiples

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To calculation the LCM that 15 and 25 by listing out the usual multiples, we can follow the given below steps:

Step 1: perform a couple of multiples that 15 (15, 30, 45, 60, 75, . . . ) and also 25 (25, 50, 75, 100, 125, 150, 175, . . . . )Step 2: The usual multiples from the multiples the 15 and also 25 space 75, 150, . . .Step 3: The smallest usual multiple that 15 and also 25 is 75.

∴ The least typical multiple the 15 and 25 = 75.

LCM that 15 and also 25 by division Method

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To calculate the LCM that 15 and also 25 through the division method, we will divide the numbers(15, 25) by your prime components (preferably common). The product of this divisors gives the LCM of 15 and 25.

Step 3: proceed the procedures until only 1s space left in the last row.

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The LCM of 15 and 25 is the product of all prime numbers on the left, i.e. LCM(15, 25) by department method = 3 × 5 × 5 = 75.