Step 2: compare the number of atoms that reactants with the number of atoms of products.

You are watching: S+hno3=h2so4+no2+h2o

 Reactants (left side) Products (right side) Element Number that atoms Number that atoms S 1 1 H 1 4 O 3 7 N 1 1

Step 3: Now, first let us take into consideration nitrogen atom. If we multiply 6 in the reactant (HNO3) and product (in NO2), us will acquire the equal variety of atoms.

 No. Of atoms of nitrogen Reactant (in HNO3) Product (in NO2) Initially 1 1 To balance 1 x 6 = 6 1 x 6 = 6

Step 4: write the result equation:

S + 6HNO3→ H2SO4 + 6NO2 + H2O

Step 5: Now check whether the equation is well balanced or no by to compare the atoms

 Reactants (left side) Products (right side) Element Number that atoms Number the atoms S 1 1 H 6 4 O 18 17 N 6 6

We uncover that the equation is not well balanced yet. Together the variety of hydrogen and also oxygen atoms are unequal top top the 2 sides.

First balance the oxygen atom.

Step 6: If us multiply 2 in the product (in H2O) and 6, us will acquire the equal variety of oxygen atom on both sides.

See more: How To Connect Storage Media On Ps3, Help Me Figure Out How To Back Up My Damn Ps3

 No. Of atoms of nitrogen Reactant (in HNO3) Product (in H2SO4+ + 6NO2+ H2O) Initially 18 17 To balance 18 4 + 12 + 2 x 1 = 18

Step 7: create the resulting equation:

S + 6HNO3→ H2SO4 + 6NO2 + 2H2O

Step 8: Now inspect whether the equation is balanced or no by comparing the atoms.

 Reactants (left side) Products (right side) Element Number the atoms Number of atoms S 1 1 H 6 6 O 18 18 N 6 6

Step 9: create the result equation: