Quadratic polynomial can be factored using the transformation ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight), where x_1 and x_2 are the solutions of the quadratic equation ax^2+bx+c=0.

You are watching: Solve 4x 2 12x 3 0

All equations of the form ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

Factor the original expression using ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight). Substitute frac32+sqrt3 for x_1 and frac32-sqrt3 for x_2.

4x^2-12x-3=4left(x-left(sqrt3+frac32
ight)
ight)left(x-left(frac32-sqrt3
ight)
ight)

4x2-12x-9 Final result : 4x2 - 12x - 9 Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 - 12x) - 9 Step 2 :Trying to factor by splitting the middle hatchet ...

displaystylex=frac32pmsqrt3displaystylexapprox-0.23quad extandquadxapprox+3.23 Explanation:Given: displaystyle ext 0=4x^2-12x-3 ...

Given that displaystyle extcosh3x+3 extcoshx=4 extcosh^3x how do you show that displaystylek^3=3k-4 has a root in between displaystyle-3 ...

https://socratic.org/questions/given-that-cosh3x-3coshx-4-cosh-3-x-how-do-you-show-that-k-3-3k-4-has-a-root-in-

The real root isdisplaystylek=-2.195823345445647 Explanation:Makingdisplaystylek=y extcoshleft(x
ight)and substituting intodisplaystylek^3=3k-4 ...

4x2-12x=-7 Two solutions were found : x =(12-√32)/8=(3-√ 2 )/2= 0.793 x =(12+√32)/8=(3+√ 2 )/2= 2.207 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign ...

4x2-12x-72 Final result : 4 • (x + 3) • (x - 6) Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 - 12x) - 72 Step 2 : Step 3 :Pulling out like terms : 3.1 Pull out ...

Given displaystylefleft(x
ight)=2^x,gleft(x
ight)=4 how do you determine the combined function displaystyley=left(f-g
ight)left(x
ight) and state ...

https://socratic.org/questions/given-f-x-2-x-g-x-4-how-do-you-determine-the-combined-function-y-f-g-x-and-state-1

displaystyley=2^x-4 Explanation:The combined functiondisplaystyley=left(f-g
ight)left(x
ight)simply means thatdisplaystyley=fleft(x
ight)-gleft(x
ight) ...

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Quadratic polynomial can be factored using the transformation ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight), where x_1 and x_2 are the solutions of the quadratic equation ax^2+bx+c=0.

All equations of the form ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

See more: Let L Be The Line In R3 That Consists Of All Scalar Multiples Of The Vector

4x^2-12x-3=4left(x-left(sqrt3+frac32
ight)
ight)left(x-left(frac32-sqrt3
ight)
ight)

Factor the original expression using ax^2+bx+c=aleft(x-x_1
ight)left(x-x_2
ight). Substitute frac32+sqrt3 for x_1 and frac32-sqrt3 for x_2.

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 4

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

Two numbers r and s sum up to 3 exactly when the average of the two numbers is frac12*3 = frac32. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u.

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