When we"re looking at the LCM (Least common Multiple), we"re looking for a number the both 12 and 15 are a factor of. Oftentimes human being simply assume the if us multiply the 2 together, we"ll discover it. In this case, it"d be #12xx15=180#. 180 is a many of both, however is that the least one? Let"s look.

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I start with a element factorization of both numbers:

#12=2xx2xx3#

#15=3xx5#

To discover the LCM, we want to have actually all the prime determinants from both numbers accounted for.

For instance, there space two 2s (in the 12). Let"s placed those in:

#LCM=2xx2xx...#

There is one 3 in both the 12 and also the 15, therefore we require one 3:

#LCM=2xx2xx3xx...#

And there is one 5 (in the 15) so let"s placed that in:

#LCM=2xx2xx3xx5=60#

#12xx5=60##15xx3=60#


Answer connect
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sjc
jan 30, 2018

#60#


Explanation:

another technique is to use teh relation

#ab=hcf(a,b)lcm(ab)#

now #hcf(12,15)=3#

#:.12xx15=3xxlcm(12,15)#

#lcm(12,15)=(cancel(12)^4xx15)/cancel(3)#

#lcm=4xx15=60#


Answer connect
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Meave60
Feb 1, 2018

The LCM is #60#.


Explanation:

The LCM is the least typical multiple. We can find the LCM by listing the multiples that the two numbers and also identifying the lowest multiple they have in common.

#12:##12,24,36,48,color(red)60,72,84...#

#15:##15,30,45,color(red)60...#

The LCM is #60#.


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Parabola
Feb 1, 2018

#60#


Explanation:

Let"s shot to find the LCM of #12# and #15#.

We get: #12=2*2*color(blue)3##15= color(blue)3*5#

We check out that lock both re-superstructure #3# is your LCM.

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We division each number by their LCM.

#12/3=>4#

#15/3=>5#

We multiply these 2 quotients and also the LCM to get our final answer:

#3*4*5=60#

That is our answer!


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