When we"re looking at the LCM (Least common Multiple), we"re looking for a number the both 12 and 15 are a factor of. Oftentimes human being simply assume the if us multiply the 2 together, we"ll discover it. In this case, it"d be #12xx15=180#. 180 is a many of both, however is that the least one? Let"s look.
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I start with a element factorization of both numbers:
#12=2xx2xx3#
#15=3xx5#
To discover the LCM, we want to have actually all the prime determinants from both numbers accounted for.
For instance, there space two 2s (in the 12). Let"s placed those in:
#LCM=2xx2xx...#
There is one 3 in both the 12 and also the 15, therefore we require one 3:
#LCM=2xx2xx3xx...#
And there is one 5 (in the 15) so let"s placed that in:
#LCM=2xx2xx3xx5=60#
#12xx5=60##15xx3=60#
Answer connect
sjc
jan 30, 2018
#60#
Explanation:
another technique is to use teh relation
#ab=hcf(a,b)lcm(ab)#
now #hcf(12,15)=3#
#:.12xx15=3xxlcm(12,15)#
#lcm(12,15)=(cancel(12)^4xx15)/cancel(3)#
#lcm=4xx15=60#
Answer connect
Meave60
Feb 1, 2018
The LCM is #60#.
Explanation:
The LCM is the least typical multiple. We can find the LCM by listing the multiples that the two numbers and also identifying the lowest multiple they have in common.
#12:##12,24,36,48,color(red)60,72,84...#
#15:##15,30,45,color(red)60...#
The LCM is #60#.
Answer connect
Parabola
Feb 1, 2018
#60#
Explanation:
Let"s shot to find the LCM of #12# and #15#.
We get: #12=2*2*color(blue)3##15= color(blue)3*5#
We check out that lock both re-superstructure #3# is your LCM.
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We division each number by their LCM.
#12/3=>4#
#15/3=>5#
We multiply these 2 quotients and also the LCM to get our final answer:
#3*4*5=60#
That is our answer!
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